2^n^-1=32

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Solution for 2^n^-1=32 equation:



2^n^-1=32
We move all terms to the left:
2^n^-1-(32)=0
We add all the numbers together, and all the variables
2^n^-33=0
We move all terms containing n to the left, all other terms to the right
2^n^=33
n=33/1
n=33

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